Parallel Operation of Transformers

Introduction:

  • For supplying a load in excess of the rating of an existing transformer, two or more transformers may be connected in parallel with the existing transformer. The transformers are connected in parallel when load on one of the transformers is more than its capacity. The reliability is increased with parallel operation than to have single larger unit. The cost associated with maintaining the spares is less when two transformers are connected in parallel.
  • It is usually economical to install another transformer in parallel instead of replacing the existing transformer by a single larger unit. The cost of a spare unit in the case of two parallel transformers (of equal rating) is also lower than that of a single large transformer. In addition, it is preferable to have a parallel transformer for the reason of reliability. With this at least half the load can be supplied with one transformer out of service.

Condition for Parallel Operation of Transformer:

  • For parallel connection of transformers, primary windings of the Transformers are connected to source bus-bars and secondary windings are connected to the load bus-bars.
  • Various conditions that must be fulfilled for the successful parallel operation of transformers:
  1.  Same voltage Ratio & Turns Ratio (both primary and secondary Voltage Rating is same).
  2. Same Percentage Impedance and X/R ratio.
  3. Identical Position of Tap changer.
  4. Same KVA ratings.
  5. Same Phase angle shift (vector group are same).
  6. Same Frequency rating.
  7. Same Polarity.
  8. Same Phase sequence.
  • Some of these conditions are convenient and some are mandatory.
  • The convenient are: Same voltage Ratio & Turns Ratio, Same Percentage Impedance, Same KVA Rating, Same Position of Tap changer.
  • The mandatory conditions are: Same Phase Angle Shift, Same Polarity, Same Phase Sequence and Same Frequency.
  • When the convenient conditions are not met paralleled operation is possible but not optimal.

 1.Same voltage Ratio & Turns Ratio (on each tap):

  •  If the transformers connected in parallel have slightly different voltage ratios, then due to the inequality of induced emfs in the secondary windings, a circulating current will flow in the loop formed by the secondary windings under the no-load condition, which may be much greater than the normal no-load current.
  • The current will be quite high as the leakage impedance is low. When the secondary windings are loaded, this circulating current will tend to produce unequal loading on the two transformers, and it may not be possible to take the full load from this group of two parallel transformers (one of the transformers may get overloaded).
  • If two transformers of different voltage ratio are connected in parallel with same primary supply voltage, there will be a difference in secondary voltages.
  • Now when the secondary of these transformers are connected to same bus, there will be a circulating current between secondary’s and therefore between primaries also. As the internal impedance of transformer is small, a small voltage difference may cause sufficiently high circulating current causing unnecessary extra I2R loss.
  • The ratings of both primaries and secondary’s should be identical. In other words, the transformers should have the same turn ratio i.e. transformation ratio.

2. Same percentage impedance and X/R ratio:

  •  If two transformers connected in parallel with similar per-unit impedances they will mostly share the load in the ration of their KVA ratings. Here Load is mostly equal because it is possible to have two transformers with equal per-unit impedances but different X/R ratios. In this case the line current will be less than the sum of the transformer currents and the combined capacity will be reduced accordingly.
  • A difference in the ratio of the reactance value to resistance value of the per unit impedance results in a different phase angle of the currents carried by the two paralleled transformers; one transformer will be working with a higher power factor and the other with a lower power factor than that of the combined output. Hence, the real power will not be proportionally shared by the transformers.
  • The current shared by two transformers running in parallel should be proportional to their MVA ratings.
  • The current carried by these transformers are inversely proportional to their internal impedance.
  • From the above two statements it can be said that impedance of transformers running in parallel are inversely proportional to their MVA ratings. In other words percentage impedance or per unit values of impedance should be identical for all the transformers run in parallel.
  • When connecting single-phase transformers in three-phase banks, proper impedance matching becomes even more critical. In addition to following the three rules for parallel operation, it is also a good practice to try to match the X/R ratios of the three series impedances to keep the three-phase output voltages balanced.
  • When single-phase transformers with the same KVA ratings are connected in a Y-∆ Bank, impedance mismatches can cause a significant load unbalance among the transformers
  • Lets examine following different type of case among Impedance, Ratio and KVA.
  • If single-phase transformers are connected in a Y-Y bank with an isolated neutral, then the magnetizing impedance should also be equal on an ohmic basis. Otherwise, the transformer having the largest magnetizing impedance will have a highest percentage of exciting voltage, increasing the core losses of that transformer and possibly driving its core into saturation.

           Case 1: Equal Impedance, Ratios and Same kVA:

  •  The standard method of connecting transformers in parallel is to have the same turn ratios, percent impedances, and kVA ratings.
  •  Connecting transformers in parallel with the same parameters results in equal load sharing and no circulating currents in the transformer windings.
  • Example: Connecting two 2000 kVA, 5.75% impedance transformers in parallel, each with the same turn ratios to a 4000 kVA load.
  • Loading on the transformers-1 =KVA1=[( KVA1 / %Z) / ((KVA1 / %Z1)+ (KVA2 / %Z2))]X KVAl
  • kVA1 = 348 / (348 + 348) x 4000 kVA = 2000 kVA.
  • Loading on the transformers-2 =KVA1=[( KVA2 / %Z) / ((KVA1 / %Z1)+ (KVA2 / %Z2))]X KVAl
  • kVA2 = 348 / (348 + 348) x 4000 kVA = 2000 kVA
  • Hence KVA1=KVA2=2000KVA

            Case 2: Equal Impedances, Ratios and Different kVA:

  •  This Parameter is not in common practice for new installations, sometimes two transformers with different kVAs and the same percent impedances are connected to one common bus. In this situation, the current division causes each transformer to carry its rated load. There will be no circulating currents because the voltages (turn ratios) are the same.
  • Example: Connecting 3000 kVA and 1000 kVA transformers in parallel, each with 5.75% impedance, each with the same turn ratios, connected to a common 4000 kVA load.
  • Loading on Transformer-1=kVA1 = 522 / (522 + 174) x 4000 = 3000 kVA
  • Loading on Transformer-1=kVA2 = 174 / (522 + 174) x 4000 = 1000 kVA
  • From above calculation it is seen that different kVA ratings on transformers connected to one common load, that current division causes each transformer to only be loaded to its kVA rating. The key here is that the percent impedance are the same.

            Case 3: Unequal Impedance but Same Ratios & kVA:

  •  Mostly used this Parameter to enhance plant power capacity by connecting existing transformers in parallel that have the same kVA rating, but with different percent impedances.
  • This is common when budget constraints limit the purchase of a new transformer with the same parameters.
  • We need to understand is that the current divides in inverse proportions to the impedances, and larger current flows through the smaller impedance. Thus, the lower percent impedance transformer can be overloaded when subjected to heavy loading while the other higher percent impedance transformer will be lightly loaded.
  • Example: Two 2000 kVA transformers in parallel, one with 5.75% impedance and the other with 4% impedance, each with the same turn ratios, connected to a common 3500 kVA load.
  • Loading on Transformer-1=kVA1 = 348 / (348 + 500) x 3500 = 1436 kVA
  • Loading on Transformer-2=kVA2 = 500 / (348 + 500) x 3500 = 2064 kVA
  • It can be seen that because transformer percent impedances do not match, they cannot be loaded to their combined kVA rating. Load division between the transformers is not equal. At below combined rated kVA loading, the 4% impedance transformer is overloaded by 3.2%, while the 5.75% impedance transformer is loaded by 72%.

              Case 4: Unequal Impedance & KVA Same Ratios:

  •  This particular of transformers used rarely in industrial and commercial facilities connected to one common bus with different kVA and unequal percent impedances. However, there may be that one situation where two single-ended substations may be tied together via bussing or cables to provide better voltage support when starting large Load.
  •  If the percent impedance and kVA ratings are different, care should be taken when loading these transformers.
  • Example: Two transformers in parallel with one 3000 kVA (kVA1) with 5.75% impedance, and the other a 1000 kVA (kVA2) with 4% impedance, each with the same turn ratios, connected to a common 3500 kVA load.
  • Loading on Transformer-1=kVA1 = 522 / (522 + 250) x 3500 = 2366 kVA
  • Loading on Transformer-2=kVA2 = 250 / (522 + 250) x 3500 = 1134 kVA
  • Because the percent impedance is less in the 1000 kVA transformer, it is overloaded with a less than combined rated load.

             Case 5: Equal Impedance & KVA Unequal Ratios:

  •  Small differences in voltage cause a large amount of current to circulate. It is important to point out that paralleled transformers should always be on the same tap connection.
  • Circulating current is completely independent of the load and load division. If transformers are fully loaded there will be a considerable amount of overheating due to circulating currents.
  • The Point which should be Remember that circulating currents do not flow on the line, they cannot be measured if monitoring equipment is upstream or downstream of the common connection points.
  • Example: Two 2000 kVA transformers connected in parallel, each with 5.75% impedance, same X/R ratio (8), transformer 1 with tap adjusted 2.5% from nominal and transformer 2 tapped at nominal. What is the percent circulating current (%IC)
  • %Z1 = 5.75, So %R’ = %Z1 / √[(X/R)2 + 1)] = 5.75 / √((8)2 + 1)=0.713
  • %R1 = %R2 = 0.713
  • %X1 = %R x (X/R)=%X1= %X2= 0.713 x 8 = 5.7
  • Let %e = difference in voltage ratio expressed in percentage of normal and k = kVA1/ kVA2
  • Circulating current %IC = %eX100 / √ (%R1+k%R2)2 + (%Z1+k%Z2)2.
  • %IC = 2.5X100 / √ (0.713 + (2000/2000)X0.713)2 + (5.7 + (2000/2000)X5.7)2
  • %IC = 250 / 11.7 = 21.7
  • The circulating current is 21.7% of the full load current.

             Case 6: Unequal Impedance, KVA & Different Ratios:

  •  This type of parameter would be unlikely in practice.
  • If both the ratios and the impedance are different, the circulating current (because of the unequal ratio) should be combined with each transformer’s share of the load current to obtain the actual total current in each unit.
  • For unity power factor, 10% circulating current (due to unequal turn ratios) results in only half percent to the total current. At lower power factors, the circulating current will change dramatically.
  • Example: Two transformers connected in parallel, 2000 kVA1 with 5.75% impedance, X/R ratio of 8, 1000 kVA2 with 4% impedance, X/R ratio of 5, 2000 kVA1 with tap adjusted 2.5% from nominal and 1000 kVA2 tapped at nominal.
  • %Z1 = 5.75, So %R’ = %Z1 / √[(X/R)2 + 1)] = 5.75 / √((8)2 + 1)=0.713
  • %X1= %R x (X/R)=0.713 x 8 = 5.7
  • %Z2= 4, So %R2 = %Z2 /√ [(X/R)2 + 1)]= 4 / √((5)2 + 1) =0.784
  • %X2 = %R x (X/R)=0.784 x 5 = 3.92
  • Let %e = difference in voltage ratio expressed in percentage of normal and k = kVA1/ kVA2
  • Circulating current %IC = %eX100 / √ (%R1+k%R2)2 + (%Z1+k%Z2)2.
  • %IC = 2.5X100 / √ (0.713 + (2000/2000)X0.713)2 + (5.7 + (2000/2000)X5.7)2
  • %IC = 250 / 13.73 = 18.21.
  • The circulating current is 18.21% of the full load current.

 3. Same polarity:

  • Polarity of transformer means the instantaneous direction of induced emf in secondary. If the instantaneous directions of induced secondary emf in two transformers are opposite to each other when same input power is fed to the both of the transformers, the transformers are said to be in opposite polarity.
  • The transformers should be properly connected with regard to their polarity. If they are connected with incorrect polarities then the two emfs, induced in the secondary windings which are in parallel, will act together in the local secondary circuit and produce a short circuit.
  • Polarity of all transformers run in parallel should be same otherwise huge circulating current flows in the transformer but no load will be fed from these transformers.
  • If the instantaneous directions of induced secondary emf in two transformers are same when same input power is fed to the both of the transformers, the transformers are said to be in same polarity.

4. Same phase sequence:

  •  The phase sequence of line voltages of both the transformers must be identical for parallel operation of three-phase transformers. If the phase sequence is an incorrect, in every cycle each pair of phases will get short-circuited.
  • This condition must be strictly followed for parallel operation of transformers.

5. Same phase angle shift:(zero relative phase displacement between the secondary line voltages):

  •  The transformer windings can be connected in a variety of ways which produce different magnitudes and phase displacements of the secondary voltage. All the transformer connections can be classified into distinct vector groups.
  • Group 1: Zero phase displacement (Yy0, Dd0, Dz0)
    Group 2:180° phase displacement (Yy6, Dd6, Dz6)
    Group 3: -30° phase displacement (Yd1, Dy1, Yz1)
    Group 4: +30° phase displacement (Yd11, Dy11, Yz11)
  • In order to have zero relative phase displacement of secondary side line voltages, the transformers belonging to the same group can be paralleled. For example, two transformers with Yd1 and Dy1 connections can be paralleled.
  • The transformers of groups 1 and 2 can only be paralleled with transformers of their own group. However, the transformers of groups 3 and 4 can be paralleled by reversing the phase sequence of one of them. For example, a transformer with Yd1 1 connection (group 4) can be paralleled with that having Dy1 connection (group 3) by reversing the phase sequence of both primary and secondary terminals of the Dy1 transformer.
  • We can only parallel Dy1 and Dy11 by crossing two incoming phases and the same two outgoing phases on one of the transformers, so if we have a DY11 transformer we can cross B&C phases on the primary and secondary to change the +30 degree phase shift into a -30 degree shift which will parallel with the Dy1, assuming all the other points above are satisfied.

6. Same KVA ratings:

  • If two or more transformer is connected in parallel, then load sharing % between them is according to their rating. If all are of same rating, they will share equal loads
  • Transformers of unequal kVA ratings will share a load practically (but not exactly) in proportion to their ratings, providing that the voltage ratios are identical and the percentage impedances (at their own kVA rating) are identical, or very nearly so in these cases a total of than 90% of the sum of the two ratings is normally available.
  • It is recommended that transformers, the kVA ratings of which differ by more than 2:1, should not be operated permanently in parallel.
  • Transformers having different kva ratings may operate in parallel, with load division such that each transformer carries its proportionate share of the total load To achieve accurate load division, it is necessary that the transformers be wound with the same turns ratio, and that the percent impedance of all transformers be equal, when each percentage is expressed on the kva base of its respective transformer. It is also necessary that the ratio of resistance to reactance in all transformers be equal.  For satisfactory operation the circulating current for any combinations of ratios and impedances probably should not exceed ten percent of the full-load rated current of the smaller unit.

7. Identical tap changer and its operation:

  • The only important point to be remembered is the tap changing switches must be at same position for all the three transformers and should check and confirm that the secondary voltages are same. When the voltage tap need change all three tap changing switches should be operated identical for all transformers. The OL settings of the SF6 also should be identical. If the substation is operating on full load condition, tripping of one transformer can cause cascade tripping of all three transformers.
  • In transformers Output Voltage can be controlled either by Off Circuit Tap Changer (Manual tap changing) or By On – Load Tap Changer-OLTC (Automatic Changing).
  • In the transformer with OLTC, it is a closed loop system, with following components:
  • (1) AVR (Automatic Voltage Regulator- an electronic programmable device). With this AVR we can set the Output Voltage of the transformers. The Output Voltage of the transformer is fed into the AVR through the LT Panel. The AVR Compares the SET voltage & the Output Voltage and gives the error signals, if any, to the OLTC through the RTCC Panel for tap changing. This AVR is mounted in the RTCC.
  • (2) RTCC (Remote Tap Changing Cubicle): This is a panel consisting of the AVR, Display for Tap Position, Voltage, and LEDs for Raise & Lower of Taps relays, Selector Switches for Auto Manual Selection… In AUTO MODE the voltage is controlled by the AVR. In manual Mode the operator can Increase / decrease the voltage by changing the Taps manually through the Push Button in the RTCC.
  • (3) OLTC is mounted on the transformer. It consists of a motor, controlled by the RTCC, which changes the Taps in the transformers.
  • Both the Transformers should have same voltage ratio at all the taps & when you run transformers in parallel, it should operate as same tap position. If we have OLTC with RTCC panel, one RTCC should work as master & other should work as follower to maintain same tap positions of Transformer.
  • However, a circulating current can be flown between the two tanks if the impedances of the two transformers are different or if the taps of the on-load tap changer (OLTC) are mismatched temporarily due to the mechanical delay. The circulating current may cause the malfunction of protection relays.

 Other necessary condition for parallel operation

  1.  All parallel units must be supplied from the same network.
  2. Secondary cabling from the transformers to the point of paralling has approximately equal length and characteristics.
  3. Voltage difference between corresponding phase must not exceed 0.4%
  4.  When the transformers are operated in parallel, the fault current would be very high on the secondary side. Supposing percentage impedance of one transformer is say 6.25 %, the short circuit MVA would be 25.6 MVA and short circuit current would be 35 kA.
  5. If the transformers are of same rating and same percentage impedance, then the downstream short circuit current would be 3 times (since 3 transformers are in Parallel) approximately 105 kA. This means all the devices like ACBs, MCCBs, switch boards should withstand the short-circuit current of 105 kA. This is the maximum current. This current will get reduced depending on the location of the switch boards, cables and cable length etc. However this aspect has to be taken into consideration.
  6. There should be Directional relays on the secondary side of the transformers.
  7. The percent impedance of one transformer must be between 92.5% and 107.5% of the other. Otherwise, circulating currents between the two transformers would be excessive.

Summary of Parallel Operation of Transformer:

 

Transformer ParallelConnection Types Equal Loading Unequal Loading Overloading Current Circulating Current Recomm. connection
Equal Impedance & Ratio ,Same KVA

Yes

 

No

No

No

Yes

 

Equal Impedance & Ratio But different KVA

No

Yes

 

No

No

Yes

 

Unequal Impedance But Same Ratio& KVA

No

Yes

 

Yes

 

No

No

Unequal Impedance & KVA But Same Ratio

No

Yes

 

Yes

 

No

No

Unequal Impedance & Ratio But Same  KVA

Yes

 

No

Yes

 

Yes

 

No

Unequal Impedance & Ratio & different  KVA

No

No

Yes

 

Yes

 

No

 

The combinations that will operate in parallel:

  • Following Vector group of Transformer will operate in parallel.

 

Operative Parallel Operation

Sr.No Transformer-1 Transformer-2

1

∆∆

∆∆ or Yy

2

Yy

Yy or ∆∆

3

∆y

∆y or Y∆

4

Y∆

Y∆ or ∆y

  • Single-phase transformers can be connected to form 3-phase transformer banks for 3-phase Power systems.
  • Four common methods of connecting three transformers for 3-phase circuits are Δ-Δ, Y-Y, Y-Δ, and Δ-Y connections.
  • An advantage of Δ-Δ connection is that if one of the transformers fails or is removed from the circuit, the remaining two can operate in the open-Δ or V connection. This way, the bank still delivers 3-phase currents and voltages in their correct phase relationship. However, the capacity of the bank is reduced to 57.7 % (1 3) of its original value.
  • In the Y-Y connection, only 57.7% of the line voltage is applied to each winding but full line current flows in each winding. The Y-Y connection is rarely used.
  • The Δ-Y connection is used for stepping up voltages since the voltage is increased by the transformer ratio multiplied by 3.

 The combinations that will not operate in parallel:

  • Following Vector group of Transformer will not operate in parallel.

 

Inoperative Parallel Operation

Sr.No Transformer-1 Transformer-2

1

∆∆

∆y

2

∆y

∆∆

3

Y∆

Yy

4

Yy

Y∆

 To check Synchronization of Transformers:

  • Synchronization of Transformer can be checked by either of following steps:
  • Checked by synchronizing relay & synchro scope.
  • If Secondary of Transformer is not LT Then we must use check synchronizing relay & Commission the system properly. After connecting relay. Relay must be charges with only 1 supply & check that relay is functioning properly.
  • Synchronizing should be checked of both the supply voltages. This can be checked directly with millimeter between L1 phases of Transformer 1 and L1 phase of Transformer 2. Then L2 Phase of Transformer 1 and L2 Phase of Transformer 2. Then L3 Phase of Transformer 1 and L3 Phase of Transformer 2. In all the cases MultiMate should show 0 voltages theoretically. These checks must be done at synchronizing breakers only. We have to also check that breaker out going terminals are connected in such a way that L1 Terminals of both the Breakers comes to same Main Bus bar of panel. Same for L2 & L3.
  • Best way to check synchronization on LT is charge complete panel with 1 source up to outgoing terminals of another incoming breaker terminal. Then just measure Voltage difference on Incoming & out going terminals of Incoming Breaker. It should be near to 0.
  • To check circulating current Synchronize both the transformer without outgoing load. Then check current. It will give you circulating current.

Advantages of Transformer Parallel Operation:

1)     Maximize electrical system efficiency:

  • Generally electrical power transformer gives the maximum efficiency at full load. If we run numbers of transformers in parallel, we can switch on only those transformers which will give the total demand by running nearer to its full load rating for that time.
  • When load increases we can switch no one by one other transformer connected in parallel to fulfil the total demand. In this way we can run the system with maximum efficiency.

2)     Maximize electrical system availability:

  • If numbers of transformers run in parallel we can take shutdown any one of them for maintenance purpose. Other parallel transformers in system will serve the load without total interruption of power.

3)     Maximize power system reliability:

  • If nay one of the transformers run in parallel, is tripped due to fault other parallel transformers is the system will share the load hence power supply may not be interrupted if the shared loads do not make other transformers over loaded.

4)     Maximize electrical system flexibility:

  • There is a chance of increasing or decreasing future demand of power system. If it is predicted that power demand will be increased in future, there must be a provision of connecting transformers in system in parallel to fulfil the extra demand because it is not economical from business point of view to install a bigger rated single transformer by forecasting the increased future demand as it is unnecessary investment of money.
  • Again if future demand is decreased, transformers running in parallel can be removed from system to balance the capital investment and its return.

Disadvantages of Transformer Parallel Operation:

  • Increasing short-circuit currents that increase necessary breaker capacity.
  • The risk of circulating currents running from one transformer to another Transformer. Circulating currents that diminish load capability and increased losses.
  • The bus ratings could be too high.
  • Paralleling transformers reduces the transformer impedance significantly, i.e. the parallel transformers may have very low impedance, which creates the high short circuit currents.
    Therefore, some current limiters are needed, e.g. reactors, fuses, high impedance buses, etc
  • The control and protection of three units in parallel is more complex.
  • It is not a common practice in this industry, since Main-tie-Main is very common in this industry.

 Conclusions:

  •  Loading considerations for paralleling transformers are simple unless kVA, percent impedances, or ratios are different. When paralleled transformer turn ratios and percent impedances are the same, equal load division will exist on each transformer. When paralleled transformer kVA ratings are the same, but the percent impedances are different, then unequal load division will occur.
  • The same is true for unequal percent impedances and unequal kVA. Circulating currents only exist if the turn ratios do not match on each transformer. The magnitude of the circulating currents will also depend on the X/R ratios of the transformers. Delta-delta to delta-wye transformer paralleling should not be attempted.

 References

  • Say, M.G. The performance and design of alternating current machines.
  • Application Guide, Loading of Transformer, Nashville, TN, USA.
  • Toro, V.D. Principles of electrical engineering.
  • Stevenson, W.D. Elements of power system analysis.
  • MIT Press, Magnetic circuits and transformers, John Wiley and Sons.
About these ads

About Jignesh.Parmar
Jignesh Parmar has completed his B.E(Electrical) from Gujarat University. He has more than 11 years experience in Power Transmission-Power Distribution-Electrical energy theft detection-Electrical Maintenance-Electrical Projects(Planning-Designing-coordination-Execution). He is Presently associate with one of the leading business group as a Assistant Manager at Ahmedabad,India. He is Freelancer Programmer of Advance Excel and design useful Excel Sheets of Electrical Engineering as per IS,NEC,IEC,IEEE codes. He is technical Author for "Electrical Mirror" and "Electrical India" Magazines. He is Technical Blogger and Familiar with English, Hindi, Gujarati, French languages. He wants to Share his experience & knowledge and help technical enthusiasts to find suitable solutions and updating themselves on various Engineering Topics.

38 Responses to Parallel Operation of Transformers

  1. sakawat says:

    Thanks

  2. Ekta says:

    any case/calculation transformer on LT side with how much short circuit current.
    Like example: 2nos. 2000Kva: 11/.433Kv transformer.

  3. Rajeev Kalaivanan says:

    My heartly thanks to u……. It’s very usefull for beginners

  4. sunil c jadhav says:

    Great Jignesh, No wors to say, I wouldlike to meet you

  5. Mouthen says:

    excellent …. many thanks

  6. Amir says:

    Great information, I have a question here. Is there any way to operate the two parallel transformer with unequal loading (considering that all the conditions for parallel operations are met)?

  7. tegemea says:

    I succeded to run three transformers in parrallel. Two of them are 10MVA connected Red Yellow Blue(ABC) and the third one 20MVA with its ABC interchanged during connection as CBA(Blue Yellow Red). I was very wondering after energizing as they run together as normal.
    Could their be any future damage for interchanging phases for the 20MVA phases?

  8. THANKS FOR YOUR INFORMATION, THIS WILL BE SURELY BE HELPFUL AND USEFULL FOR BOTH FRESH ENGINEERS ALSO FOR PRACTICING ENGINEERS ON SITE AS A A READY RECOKENER, GUIDE BOOK.

  9. Vasuki says:

    Dear Jignesh, I have a question regarding parallel opeartion of two feeders.
    we have two incomers coming from the electricity boards,but are from different sources. we have bus coupler between the two incomers. when we checked the two voltages for synchronism, we found phase sequence , phasing, frequency are same. only minor difference in voltage , less than 0.5%. can we make parallel operation in case of emergency through bus coupler. Plerase let me know. my e mail ID is raovasuki17@gmail.com

  10. Nice matter says:

    Good

  11. kulasekhar says:

    nice article more useful

  12. KISHAN GAMI says:

    i salute u…sir…for your enormous work….its more than a book or encyclopedia ..really nice work…

    sir please give me information about steps to keep in mind while choosing a correct power transformer…..about all the ratings how to decide in detail…..as fast as possible….

  13. Bhuwesh kumar says:

    thank u sir……………..it was treat to read……….plz add material for motor to……

  14. ajit pimple says:

    hi , Mr Jagdish
    thanks for very usfull information, We are ahmedabad based transformer manufacturing co., can you send you contact detail on my mail ID. we have to devlope some excel base designing tools.
    Thanks again

  15. ashish rathod says:

    dear sir, i am in diploma electrical engineering , my hobby is learns about every electrical equipment, so u can help to find which is the best learning web site for electrical students..
    thank u.

  16. nebri says:

    i have not enough word to explain my thanks

  17. Anant says:

    Thanks.It help me a lot for explaining to the student.

  18. naveen b says:

    hi sir,
    Please guide for Earthing calculations according to IS standards.

  19. vishal Gor says:

    Thanks

  20. wjfgi says:

    cant understand

  21. HARI says:

    lot of thanks to jignesh sir to provide these use full matter

  22. sunil says:

    Excellent description …..

  23. Rafiullah Khan says:

    Thats great job,,,

  24. ahmed says:

    Excellent. Thanks

  25. manoj kumar says:

    Thanks sir,

  26. periyasamy says:

    Dear Sir,

    Thank you very much. this very use full to me for 2 transformer parellel operations. i having lot of electrical doughts can you help me.

  27. periyasamy says:

    sir,

    we have single 11kv source from eb than two transformer from 2 ocb this HT side after 2 saperate feeder 2 acb in between 1 bus coupler now both transformer is loaded different load. now my question is i’ll close bus coupler what will hapen any short circuit or both transformer will shared the load without any damage. please guide me sir

  28. aj says:

    were is circuit diagram….

  29. Narendra n Chandratre says:

    Dear sir,
    Presently we are using 1250 KVA 22Kv/433 v transformer having impedance of 5.75%. Now due to increase in demand we are planning to add another transformer of 1600 Kva capacity. will you please guide me to make safe operation for continious use?
    What care we must take care while ordering the new transformer. I will like to understand how to check % impedance ,Recactance resistance X/R of the transformer requested to guide by consedering our case of transformer capacity.
    It will be more suitable to us to calculate even breaker capacity so as to be safe in faulty condition.
    existing transformer is equiped with OLTC ( +5% to -15%)
    Requested to guide
    Thanks
    Narendra

  30. Ekta says:

    Please suggest 2000KVA 11/.415KV 4nos. transformer can be paralleled with tentative calculation. Percentage impedance varies 6.07 to 6.2. all trafos are delta/star.

  31. PRASHANT SONI says:

    Dear Sir,
    Thank you from the bottom of my heart to ur valuable information and ur sincere & noble work..

  32. Denish says:

    I have a 7.5 MVA trafo with following specification:
    DYn1, 22 kV / 6.6 kV.
    Problem : Mismatch of Phase seq. at panel end as connectivity is thro. busduct. At 6.6 kV level of trafo. phase sequence is B-Y-R but i want it to change with R-Y-B. Can i interchange primary (22 kV) cable phase seq. by R-Y-B to B-Y-R to get desire Phase seq. at secondory (6.6 kV). what will happen to vector group. pl. advise.

  33. GILY ONGOGO says:

    really good site for electrical ideas

  34. selvaraj says:

    good one,what shall be the permisible phase angle diff for paralleling two feeders from different sources.

  35. Riyaz says:

    Dear Jignesh,

    We have a peculiar issue for the paralleling of two transformers serving a MV loop – which serves 3 Nos of 100 kVA transformers +1 No 500 kVA transformers.

    The substation (LV end) feeding the two transformers is powered two 100 kVA transformers and the ACB rating is 800A

    The detail of the two transformers is as under.

    Sl No Description Parameters
    Step-up -1 Step-up-2
    1 Transformer Rating 500/700KVA ANAF 500/700KVA ANAF
    2 Transformer Impedance 6.30% 5.30%
    3 Transformer Tap setting 11261 11275
    4 Vector Group Dyn11 Dyn11
    5 Voltage measured on capacitive indicator of the RMU between the two MV feeds varies
    between 7V, 8.8V and 10 V on respective R Phase Y Phase and B Phase respectively

    Please advise what will be the circulating current and its effect on the transformer /LV feeder while the transformers are momentarily paralleled for which the duration may exceed to 7 minutes.

    Thanks
    Riyaz

Leave a Reply

Fill in your details below or click an icon to log in:

WordPress.com Logo

You are commenting using your WordPress.com account. Log Out / Change )

Twitter picture

You are commenting using your Twitter account. Log Out / Change )

Facebook photo

You are commenting using your Facebook account. Log Out / Change )

Google+ photo

You are commenting using your Google+ account. Log Out / Change )

Connecting to %s

Follow

Get every new post delivered to your Inbox.

Join 3,552 other followers

%d bloggers like this: